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Q.63. The heat generated in a circuit is given by $Q = I^{2} R t$ , where I is current, R is resistance and t is time. If errors in measuring current, resistance and time are 2 %, 1 % and 1 %, respectively, the maximum error in measuring heat will be
(1) 2 %
(2) 4 %
(3) 6 %
(4) 8 %

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Solution

Dear Student ,

$(∆ H) / H = 2 * (∆ I) / I + (∆ R) / R + (∆ t) / t S o p e r c e n t a g e e r r o r i n H = (2 \times 1 + 1 + 1) % = 4 %$
Regards

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solve this Q.63. The heat generated in a circuit is given by Q=I2 Rt, where I is current, R is resistance and t is time. If errors in measuring current, resistance and time are 2 %, 1 % and 1 %, respectively, the maximum error in measuring heat will be (1) 2 % (2) 4 % (3) 6 % (4) 8 %

Dear Student , ( ∆ H) /H= 2*(∆ I)/I +( ∆R)/R +( ∆ t)/t So percentage error in H = 2×1+1+1 %=4% Regards

solve this
Q.63. The heat generated in a circuit is given by $Q = I^{2} R t$ , where I is current, R is resistance and t is time. If errors in measuring current, resistance and time are 2 %, 1 % and 1 %, respectively, the maximum error in measuring heat will be
(1) 2 %
(2) 4 %
(3) 6 %
(4) 8 %

Dear Student ,

$(∆ H) / H = 2 * (∆ I) / I + (∆ R) / R + (∆ t) / t S o p e r c e n t a g e e r r o r i n H = (2 \times 1 + 1 + 1) % = 4 %$
Regards