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Byju's Answer
Standard XII
Mathematics
Equation of Normal for General Equation of a Circle
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Question
Solve this:
Q.82. The equation of tangent to circle
x
2
+
y
2
+
4
x
-
4
y
+
4
=
0
that make intercepts on positive co-ordinate axes is
(a) x + y = 2
(b) x + y = 2
2
(c) x + y = 4
(d) x + y = 8
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Solution
Hi
,
x
2
+
y
2
+
4
x
-
4
y
+
4
=
0
comparing
it
with
x
2
+
y
2
+
2
gx
+
2
fy
+
c
=
0
so
center
=
-
g
,
-
f
=
-
2
,
2
and
radius
=
g
2
+
f
2
-
c
=
4
+
4
-
4
=
2
Now
let
the
equation
of
the
required
tangent
be
x
+
y
=
a
and
taking
x
+
y
=
a
because
intercept
form
of
line
is
x
a
+
y
b
=
1
and
since
intercept
is
equal
so
let
it
is
a
,
and
since
a
=
b
so
taking
both
as
a
x
+
y
=
a
then
length
of
the
perpendicular
from
centre
=
radius
-
2
+
2
-
a
1
2
+
1
2
=
2
a
=
2
2
hence
the
equation
of
tangent
is
x
+
y
=
2
2
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