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Electrolytic Cell

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Solve this:
Q. If the standard electrode potential of $C u^{2 +}$ /Cu electrode is 0.34 V, what is the electrode potential of 0.1 M concentration of $C u^{2 +}$ ?
(1) 3.99 V
(2) 0.3105 V
(3) 0.222 V
(4) 0.176 V

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Solution

Dear student ,
E_cell = E_cell⁰ - o.0592 /n log (product) / (reactant)
in the given question ; Cu⁺⁺ + 2 e^- = Cu
E_cell = 0.34 - 0.0592 / 2 log ( Cu) / Cu⁺⁺
= 0.34 - 0.0592 / 2 log 1 / 0.1
= 0.3105 V (option 2)
Regards

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