Solve this equation H3Po4+3Ca(OH2)=HOH+Ca3(Po4)

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Solution

Looking at Ca3(PO4)2 you know you need at least 3 Ca(OH)2 and 2 H3PO4 this leaves 6 H2Os

3 Ca(OH)2 + 2 H3PO4 -> Ca3(PO4)2 + 6 H2O

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Solve this equation H3(Po4)+Ca(OH2)=HOH+Ca3(Po4) I want this method of balance

{C a C O}_{3}

H_{3} P O_{4}

{C a}_{3} ({P O}_{4})_{2}

\frac{35 p + 5}{12} = 15

\frac{5 x}{3} + \frac{2}{5} = 1

2 x - 3 y = 9; 2 x + y = 13

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