solve this :- sin i/sin r = n , where , n=1.5 and /_i=30. Find the value of /_r.

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Solution

Dear Student

$n = \frac{\sin i}{\sin r} 1.5 = \frac{\sin 30^{0}}{\sin r} \sin r = \frac{\sin 30^{0}}{1.5} = \frac{0.5}{1.5} = 0.33 r = \sin^{- 1} (0.33) = 19 . 26^{0}$

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