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Byju's Answer
Standard XII
Mathematics
Continuity in an Interval
Solve : x → ...
Question
Solve :
lim
x
→
0
[
tan
x
x
]
Open in App
Solution
lim
x
→
0
[
tan
x
x
]
at
x
→
0
⇒
tan
x
≥
x
∴
tan
x
x
∈
[
1
,
2
]
as
x
→
0
∴
lim
x
→
0
[
tan
x
x
]
=
lim
x
→
0
1
=
1
. Answer.
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0
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