wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve Ltx0x23xx1cos(3x)

A
29log2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
23log4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
43log2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
13log2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 29log2
limx0x23xx1cos(3x)=00 form.
by L,Hospital's Rule.
limx023x+x23xlog213(sin3x)=00 From again L' Hospital's Rule.
limx023x+1log2+x.23x(log2)29cos3x=2log29 Ans

1110054_1180878_ans_1c40344d601e46c09d0afb39f375d8c9.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
All Strings Attached
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon