Solve using a3-b3 identity 3-3x2-y3 -

3√(3)x^2+y^3 [∵ a^3+b^3=(a+b)^3 3a^2b 3ab^2] (3√(3)x^2+y^3)^3 3× 9× 3x^4y^3 3√(3)x^2y^6 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

(x+y)^2 + (x-y)^2 and (x+y)^2 - (x-y)^2

Solve using ...

Question

Solve using $a^{3} + b^{3}$ identity $3 \sqrt{3} x^{2} + y^{3}$ ?

Open in App

Solution

Suggest Corrections

Similar questions

Which of the following is an expansion of the identity ${(a - b)}^{3}$ ?

a^{3} {(b - c)}^{3} + b^{3} {(c - a)}^{3} + c^{3} {(a - b)}^{3}

(a + b)^{3} - a^{3} - b^{3}

\sqrt{\frac{(a^{3} - b^{3})^{5}}{a^{3} - b^{3}}}

125 a^{3} + b^{3} + 64 c^{3} - 60 a b c

a^{3} + b^{3} + c^{3} - 3 a b c = \frac{1}{2} (a + b + c) [{(a - b)}^{2} + {(b - c)}^{2} + {(c - a)}^{2}]

Join BYJU'S Learning Program