_{solve using BODMAS:}

_{QUES- 5+3{-34-line bracket on 16-14}÷3[17+(-3)×4-2×(-17)]}

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Solution

This can be done by BODMASS Rule

5+3{-34-16-14}÷3[17+(--3)4-2(-7)]

5+3{-64}÷ 3[17-12+14]

5-192/3(19)

-187/3(19)

hope helped!

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45 + 3 {34 - 18 - 14} \div 3 {17 + 3 \times 4 - (2 \times 7)]

Prove that:
(i) $\frac{1}{3 + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + 1} = 1$
(ii) $\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{9}} = 2$