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Byju's Answer
Standard XII
Mathematics
Special Integrals - 2
Solve using l...
Question
Solve using logarith:
4*7
2x
+ 7
x+1
- 2 = 0
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Solution
4
×
7
2
x
+
7
x
+
1
-
2
=
0
Let
7
x
=
t
4
t
2
+
7
t
-
2
=
0
4
t
2
+
8
t
-
t
-
2
=
0
4
t
t
+
2
-
1
t
+
2
=
0
4
t
-
1
t
+
2
=
0
t
=
-
2
or
1
4
Now
equating
the
assumed
we
get
,
7
x
=
-
2
or
7
x
=
1
4
But
7
x
=
-
2
is
not
possible
because
LHS
will
always
be
positive
.
so
7
x
=
1
4
Taking
log
we
get
,
log
7
x
=
log
1
4
xlog
7
=
-
log
4
x
=
-
log
4
log
7
=
-
log
7
4
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