Question

Solve using quadratic formula,
$3x^2+2(3+2a)x+8a=0$

Answer 1

$3x^2+2(3+2a)x+8a=0$

$3x^2+(6+4a)x+8a=0$

$x=\frac{-(6+4a)\pm \sqrt{{(6+4a)}^2-4\cdot 3\cdot 8a}}{2\cdot 3}$

$x=-2,-\frac{4a}{3}$