Question

Solve using quadratic formula,
$ab{x}^2-(a^2+b^2)x+ab=0$

Answer 1

$ab{x}^2-(a^2+b^2)x+ab=0$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-a^2-b^2)\pm \sqrt{{(-a^2-b^2)}^2-4abab}}{2ab}$

$x=\frac{a}{b},\frac{b}{a}$