Question

Solve using the Quadratic formula.
$3m^2+2m-7=0$.

Answer 1

The quadratic formula for the standard Quadratic equation of the form :

$a{x}^2+bx+c=0$ is :

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Now Comparing the given equation $3m^2+2m-7=0$ to the standard form we get:

$a=3$,

$b=2$ and

$c=-7$

Substituting value of a,b and c in the quadratic formula we get:

$x=\frac{-2\pm \sqrt{2^2-4\times 3\times (-7)}}{2\times 3}$

$\Rightarrow x=\frac{-2\pm \sqrt{88}}{6}$

$\Rightarrow x=\frac{2\times (-1\pm \sqrt{22})}{2\times 3}$

$\therefore$ $x=\frac{(-1+\sqrt{22})}{2}$ or $x=\frac{(-1-\sqrt{22})}{2}$