Solve:
$(x - 1) (x + 6) - (x - 2) (x - 3) = 3$

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Solution

$(x - 1) (x + 6) - (x - 2) (x - 3) = 3$

$\Rightarrow (x^{2} - x + 6 x - 6) - (x^{2} - 2 x - 3 x + 6) = 3$

$\Rightarrow x^{2} + 5 x - 6 - x^{2} + 5 x - 6 = 3$

$\Rightarrow 10 x - 12 = 3$

$\Rightarrow 10 x = 12 + 3$

$\Rightarrow x = \frac{15}{10} = \frac{3}{2}$

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Similar questions

Solve the following equations :

$(x - 1) (x + 6) - (x - 2) (x - 3) = 3$

\frac{(x - 1) (x - 2) (x - 3)}{(x + 1) (x + 2) (x + 3)} > 1

\frac{(x - 1) (x - 2) (x - 3)}{(x + 1) (x + 2) (x + 3)} > 1

x :

2 (x + 1) (x + 3) + 8 = (2 x + 1) (x + 5)

x : \frac{1}{(x - 1) (x - 2)} + \frac{1}{(x - 2) (x - 3)} + \frac{1}{(x - 3) (x - 4)} = \frac{1}{6}

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