Solve: $x + 11 = 40$

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Solution

The given expression is $x + 11 = 40$
Transposing $11$ to RHS, we get
$\begin{array}{rcl} x & = & 40 - 11 \\ = & 29 \end{array}$

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40 . If \tan^{- 1} \frac{\sqrt{1 + x^{2}} - 1}{x} = \frac{π}{45}, then (1) x = \tan 2 ° (2) x = \tan 4 ° (3) x = \tan {(\frac{1}{4})}^{°} (4) x = \tan 8 °

tan ({cos}^{- 1} \frac{1}{x}) = sin ({cot}^{- 1} \frac{1}{x})

\frac{3}{11} + x = \frac{9}{11}

x

Solve

13x + 11y = 70

11x + 13y = 74

\frac{x - 15}{x - 11} = 2

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