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Quadratic Equations

Solve : x2+1...

Question

Solve :
$x^{2} + 15 x + 36 = 0$

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Solution

We have,
$x^{2} + 15 x + 36 = 0$

$= x^{2} + x (12 + 3) + 36 = 0$

$= x^{2} + 12 x + 3 x + 36 = 0$

$= x (x + 12) + 3 (x + 12) = 0$

$= (x + 12) (x + 3) = 0$

$= x = - 12,$ or $x = - 3$

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