Question

Solve: $x^2-3\sqrt{6}x+12=0$

Answer 1

Now,

$x^2-3\sqrt{6}x+12=0$

or, $x^2-2\sqrt{6}x-\sqrt{6}x+12=0$

or, $x(x-2\sqrt{6})-\sqrt{6}(x-2\sqrt{6})=0$

or, $(x-\sqrt{6})(x-2\sqrt{6})=0$

or, $x=\sqrt{6}$ or $x=2\sqrt{6}$.