Question

Solve

$x^2+3x+5=0$

Answer 1

Here $x^2+3x+5=0$

Comparing the given quadratic equation with

$a{x}^2+bx+c=0$ we have

$a=1,b=3$ and $c=-5$

$\therefore x=\frac{-3\pm \sqrt{(3{)}^2-4\times 1\times 5}}{2\times 1}$

$=\frac{-3\pm \sqrt{11}}{2}=\frac{-3\pm \sqrt{11}i}{2}$

Thus $x=\frac{-3+\sqrt{11}i}{2}$ and $x=\frac{-3-\sqrt{11}i}{2}$