The correct option is A { 1,5 } ⇒ #160; x^2 4x 5=0 ⇒ #160; x^2 5x+1x 5=0 ⇒ #160; x(x 5)+1(x 5)=0 ⇒ #160; ...

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Quadratic Formula

Solve x2-4x...

Question

Solve $x^{2} - 4 x - 5 = 0$

{- 1, 5}

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{1, 5}

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{- 1, - 5}

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None of these

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Solution

The correct option is A ${- 1, 5}$
$\Rightarrow$ $x^{2} - 4 x - 5 = 0$
$\Rightarrow$ $x^{2} - 5 x + 1 x - 5 = 0$
$\Rightarrow$ $x (x - 5) + 1 (x - 5) = 0$
$\Rightarrow$ $(x - 5) (x + 1) = 0$
$\Rightarrow$ $x - 5 = 0$ and $x + 1 = 0$
$∴$ $x = 5$ and $x = - 1$

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