Solve: $x^{2} - 5 x + 24 = 0$

Open in App

Solution

Let $x^{2} - 5 x + 24 = 0$
$\Rightarrow$ $x^{2} - 8 x + 3 x + 24 = 0$
$\Rightarrow$ $x (x - 8) - 3 (x - 8) = 0$
$\Rightarrow$ $(x - 8) (x - 3) = 0$
$\Rightarrow$ $x - 8 = 0$ and $x - 3 = 0$
$∴$ $x = 8$ and $x = 3$

Suggest Corrections

Similar questions

Simplify : $\frac{x^{2} - 5 x - 24}{(x + 3) (x + 8)} \times \frac{x^{2} - 64}{{(x - 8)}^{2}}$

\frac{1 + x^{2}}{x^{2} - 5 x + 6} < 0

x^{2} - 5 x - 36 = 0

x^{2} - 5 x + 4 = 0

x^{2} - 5 x - 14 = 0

Join BYJU'S Learning Program