solve: $x^{2} - 6 x - 27$ .

Open in App

Solution

$x^{2} - 6 x - 27$
$= x^{2} - 9 x + 3 - 27$
$= (x - 9) (x + 3)$

Suggest Corrections

Similar questions

x^{2} + 6 x - 27 = 0

x^{2} + 6 x = 27

Simplify:
(i) $x^{2} - 6 x = 27$
(ii) $x^{2} + 6 x - 10 = 0$

{log}_{\frac{- x^{2} - 6 x}{10}} (sin 3 x + sin x) = {log}_{\frac{- x^{2} - 6 x}{10}} (sin 2 x)

x^{2} + 2 \sqrt{x^{2} + 6 x} = 24 - 6 x

Join BYJU'S Learning Program