Solve :
$x^{2} + 6 x - 27 = 0$

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Solution

given, $x^{2} + 6 x - 27 = 0$

$x^{2} + 9 x - 3 x - 27 = 0$

$x (x + 9) - 3 (x + 9) = 0$

$(x + 9) (x - 3) = 0$

$x = 3, - 9$

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Similar questions

x^{2} - 6 x - 27

Simplify:
(i) $x^{2} - 6 x = 27$
(ii) $x^{2} + 6 x - 10 = 0$

x^{2} + 6 x = 27

x^{2} + 6 x + 13 > 0

x^{2} - 6 x + 8 > 0

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