Solve :
$x^{2} - 6 x + 5 = 0$

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Solution

given, $x^{2} - 6 x + 5 = 0$

$x^{2} - 5 x - x + 5 = 0$

$x (x - 5) - 1 (x - 5) = 0$

$(x - 5) (x - 1) = 0$

$x = 5, 1$

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