Question

Solve : $x^2-6x+7=0$

Answer 1

Consider the given equation.

$x^2-6x+7=0$

$x^2-6x+7=0$

Now,

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-6)\pm \sqrt{(-6{)}^2-4\times 1\times 7}}{2\times 1}$

$x=\frac{6\pm \sqrt{36-28}}{2}$

$x=\frac{6\pm \sqrt{8}}{2}$

$x=\frac{6\pm 2\sqrt{2}}{2}$

$x=3\pm \sqrt{2}$

Hence, this is the answer.