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Question

Solve x2+6x7=0 by the method of completing the square

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Solution

Solution:
Completing the square method:
x2+6x=7
Adding [12×coefficient ofx]2 both sides we get,
x2+6x+[12×6]2=7+[12×6]2
or, x2+6x+32=7+32
or, (x+3)2=16
or, x+3=16
or, x+3=±4
or, x=43 or x=43
or, x=1 or x=7

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