Question

Solve $x^2+7x=7$ and give your answer correct to two decimal places.

Answer 1

Given equation is $x^2+7x=7$

$\Rightarrow x^2+7x-7=0$

Using the quadratic formula, we get:

$x=\frac{-7\pm \sqrt{49+28}}{2\times 1}$

$\Rightarrow x=\frac{-7\pm \sqrt{77}}{2}=0.89,-7.89$

Thus, there are two values of $x$ i.e $0.89$ and $-7.89$ (correct up to two decimal places)