Solve
x2−x+2=0
Here x2−x+2=0
Comparing the given quadratic equation with
ax2+bx+c=0 we have
a=1,b=−1 and c=2
∴x=−1(−1)±√(−1)2−4×1×22×1
=1±√−72=1±√7i2
Thus x=1+√7i2 and x=1−√7i2
x2+x√2+1=0
x2+x+1√2=0
x2+3=0
x2+3x+5=0
x2+3x+9=0