Solve
−x2+x−2=0
Here −x2+x−2=0
Comparing the given quadratic equation with
ax2+bx+c=0 we have
a=−1,b=1 and c=−2
∴x=−1±√(1)2−4×−1×−22×−1
=−1±√1−8−2=−1±√−7−2
=−1±√−7i−2
Thus x=−1+√7i−2 and x=−1−√7i−2