Question

Solve $x^2-x-2>0$.

Answer 1

$x^2-x-2=x^2-2x+x-2$
$=x(x-2)+1(x-2)$
$\therefore x^2-x-2=(x-2)(x+1)$
So, given expression can be written as $(x+1)(x-2)>0$
$⟹\in (-\infty ,-1)\bigcup (2,\infty )$