Solve:
$x - 2 y = 0 a n d 3 x - y = 5$

x = 2, y = 2

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x = 2, y = 1

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x = 2, y = 4

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x = 1, y = 2

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Solution

The correct option is B $x = 2, y = 1$
Given,
$x - 2 y = 0... (1)$
$3 x - y = 5... (2)$

From (1),
$x = 2 y$
Substituting this value of $x$ in (2),
$3 (2 y) - y = 5 ⟹ 5 y = 5 ⟹ y = 1$

Now,
$x = 2 y ⟹ x = 2 \times 1 = 2$

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\frac{1}{2 (x + 2 y)} + \frac{5}{3 (3 x - 2 y)} = \frac{- 3}{2} \frac{5}{4 (x + 2 y)} - \frac{3}{5 (3 x - 2 y)} = \frac{61}{60}

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