We have,
−x+3+(−19)+15+(−10)=0
−x+3−19+15−10=0
−x−16+5=0
−x−11=0
x=−11
Hence, the value of x is −11.
Solve each of the following systems of equations by using the method of cross multiplication:
x6+y15=4,x3−y12=194.
1) X/6+y/15=4
X/3-y/12=19/4
Solved it by elimination of substitution
Solve the following pair of equations: 7x - 15y = 2 ; x + 2y = 3. Hence find 'm' in y = mx - 30/29
Solve:
log (5x + 19) = log( 7x + 3)