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Question

Solve:
$$x^{4}-16\div x+2$$


Solution

$$\cfrac{{x}^{4}-16}{x+2}$$
So $${x}^{4}-16=({x}^{2}+4)({x}^{2}-4)$$
now $${x}^{2}-4=(x+2)(x-2)$$
So $$\cfrac { \left( { x }^{ 2 }+4 \right) \left( x+2 \right) \left( x-2 \right)  }{ x+2 } =\left( { x }^{ 2 }+4 \right) \left( x-2 \right) $$

Mathematics

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