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Byju's Answer
Standard X
Mathematics
Elimination Method to Find the Solution of Pair of Linear Equations
Solve: x+4y...
Question
Solve:
x
+
4
y
=
14
and
7
x
−
3
y
=
5
A
x
=
2
,
y
=
3
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B
x
=
5
,
y
=
3
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C
x
=
6
,
y
=
−
4
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D
x
=
−
3
,
y
=
7
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Solution
The correct option is
A
x
=
2
,
y
=
3
Given equations are
x
+
4
y
=
14
....(1)
and
7
x
−
3
y
=
5
....(2)
Let us slove equation (2) as
7
x
=
5
+
3
y
⇒
x
=
5
+
3
y
7
....(3)
Put this value in equation (1), we get
5
+
3
y
7
+
4
y
=
14
⇒
5
+
3
y
+
28
y
=
98
⇒
31
y
=
93
⇒
y
=
3
Substitute this value of
y
in equation (3),
x
=
5
+
3
(
3
)
7
⇒
x
=
14
7
⇒
x
=
2
Therefore, the solution is
x
=
2
,
y
=
3
.
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Similar questions
Q.
Solve for
x
and
y
:
y
+
7
5
=
2
y
−
x
4
+
3
x
−
5
,
7
−
5
x
2
+
3
−
4
y
6
=
5
y
−
18
Q.
Solve the following simultaneous equations graphically.
(1)
x
+
y
= 6 ;
x
–
y
= 4
(2)
x
+
y
= 5 ;
x
–
y
= 3
(3)
x
+
y
= 0 ; 2
x
–
y
= 9
(4) 3
x
–
y
= 2 ; 2
x
–
y
= 3
(5) 3
x
– 4
y
= –7 ; 5
x
– 2
y
= 0
(6) 2
x
– 3
y
= 4 ; 3
y
–
x
= 4