Question

Solve: $(x^6-3x^4+2x^2)÷3x^2$

Answer 1

$(x^6-3x^2+2x^2)÷3x^2$
$=\frac{x^6-3x^4+2x^2}{3x^2}$
$=\frac{x^6}{3x^2}-\frac{3x^4}{3x^2}+\frac{2x^2}{3x^2}$
$=\frac{1}{3}{x}^4-x^2+\frac{2}{3}$
Alternative Method:
We can find the common factor $x^2$ and simplify it as
$\frac{x^6-3x^4+2x^2}{3x^2}=\frac{x^2(x^4-3x^2+2)}{3x^2}$
$=\frac{1}{3}(x^4-3x^2+2)$
$=\frac{x^4}{3}-x^2+\frac{2}{3}$