Solve:
$x + 6 - 3 x - 5 - 2 (x - 5) = 2 x - 9 - 2 x + 5 - 3 (x + 1)$

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Solution

$x + 6 - 3 x - 5 - 2 (x - 5) = 2 x - 9 - 2 x + 5 - 3 (x + 1)$
$\Rightarrow x + 6 - 3 x - 5 - 2 x + 10 = - 9 + 5 - 3 x - 3$
$\Rightarrow - x + 11 = - 7$
$\Rightarrow x = 11 + 7$
$\Rightarrow x = 18$ .

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Similar questions

2 x \leq x - 1 < 3 x + 5

3 x + 5 = 2 x - 6

\frac{2 x - 3}{2 x - 1} = \frac{3 x - 1}{3 x + 5}

2 x - 5 [7 - (x - 6) + 3 x] - 28 = 39

Solve the equations:

(i) 5x = 3x + 24;

(ii) 8t + 5 = 2t − 31;

(iii) 7x − 10 = 4x + 11;

(iv) 4z + 3 = 6 + 2z;

(v) 2x − 1 = 14 − x;

(vi) 6x + 1 = 3(x − 1) + 7;

(vii) ;

(viii) ;

(ix) 3(x + 1) = 12 + 4 (x − 1);

(x) 2x − 5 = 3(x − 5);

(xi) 6(1 − 4x) + 7(2 + 5x) = 53;

(xii) 3(x + 6) + 2 (x + 3) = 64;

(xiii) ;

(xiv) .

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