Question

Solve:

$x\sin {45}^o.\cos {45}^o.\tan {60}^o=\tan {45}^o-\cos {60}^o$.

Answer 1

Now,

$x\sin {45}^o.\cos {45}^o.\tan {60}^o=\tan {45}^o-\cos {60}^o$

or, $x.\frac{1}{\sqrt{2}}.\frac{1}{\sqrt{2}}.\sqrt{3}=1-\frac{1}{2}$

or, $\frac{\sqrt{3}x}{2}=\frac{1}{2}$

or, $x=\frac{1}{\sqrt{3}}$.