Solve: $y^{2} + 2 y - 48$

Open in App

Solution

$y^{2} + 2 y - 48$
$= y^{2} + 8 y - 6 y - 48$
$= y (y + 8) - 6 (y + 8)$
$= (y + 8) (y - 6)$
$∴ y^{2} + 2 y - 48 = (y + 8) (y - 6)$ .

Suggest Corrections

Similar questions

2 y^{3} + y^{2} - 2 y - 1

y^{2} - 2 y - 99 = 0

(x^{2} - y^{2}) \times (x + 2 y)

5 (2 x + y)^{2} - (2 x + y) (x - 2 y)

Solve y² +1/2y-1=0 by Factorisation

Join BYJU'S Learning Program

Related Videos

(a + b)^2 Expansion and Visualisation

MATHEMATICS

Watch in App

Explore more

Join BYJU'S Learning Program