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4x $^{2}$ + 8x

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Solution

$4 x^{2} + 8 x 4 x (x + 2)$
$x = 0, - 2$

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Solve

4x – 2y = 10
x + y = 4

(x-1/2)*1/2=3/8

x/2*1/2=3/8

x/4=3/8

x=3/2

x=1.5

Why is this not correct?

Q. Solve:

2 x + 8 x + 1 + (8 x + 1)^{2}

Choose the correct answer in the given question.
$\int \sqrt{x^{2} - 8 x + 7} d x$ is equal to
$(a) \frac{1}{2} (x - 4) \sqrt{x^{2} - 8 x + 7} + 9 l o g | x - 4 + \sqrt{x^{2} - 8 x + 7} | + C (b) \frac{1}{2} (x + 4) \sqrt{x^{2} - 8 x + 7} + 9 l o g | x + 4 + \sqrt{x^{2} - 8 x + 7} | + C (c) \frac{1}{2} (x - 4) \sqrt{x^{2} - 8 x + 7} - 3 \sqrt{2} l o g | x - 4 + \sqrt{x^{2} - 8 x + 7} | + C (d) \frac{1}{2} (x - 4) \sqrt{x^{2} - 8 x + 7} - \frac{9}{2} l o g | x - 4 + \sqrt{x^{2} - 8 x + 7} | + C$

Q. How to factorise 8x^3-8x^2-9

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solve4x2 + 8x

4x2+8x4x(x+2)x=0,−2

solve
4x $^{2}$ + 8x

$4 x^{2} + 8 x 4 x (x + 2)$
$x = 0, - 2$