Solving sin-3-2 then- - n- - -1 n-m-n- I- Find m

sinθ=√(3)/2 ⇒sinθ = sinπ/3 ∴θ= nπ + ( 1 )^nπ/3,n∈ I ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

General Solution of Trigonometric Equation

Solving sin...

Question

Solving $sin θ = \frac{\sqrt{3}}{2}$ then, $θ = n π + {(- 1)}^{n} \frac{π}{m}, n \in I$ . Find $m$

Open in App

Solution

$sin θ = \frac{\sqrt{3}}{2}$
$\Rightarrow sin θ = sin \frac{π}{3}$
$∴ θ = n π + {(- 1)}^{n} \frac{π}{3}, n \in I$

Suggest Corrections

Similar questions

Q. Solve

cos 3 x + sin 2 x - sin 4 x = 0

, then

x = (2 n + 1) \frac{π}{m}, n \in I

n π + {(- 1)}^{n} \frac{π}{m}, n \in I

. Find the value of

m

Q. Solve

{cos}^{2} θ = \frac{1}{2}

, then

θ = n π \pm \frac{π}{m}, n \in I

. Find the value of

m

Consider the system of linear equations in x, y and z ;
(sin 3 $θ$ ) x - y + z = 0 ......(i)
(cos 2 $θ$ )x + 4y + 3z = 0 ......(ii)
2x + 7y+ 7z = 0 ......(iii)

The value of $θ$ for which the system has nontrivial solution is

Q. The general values of

θ

satisfying the equation

2 s i n^{2} θ - 3 s i n θ - 2 = 0

(n \in Z)

Q. The general solution of

(\sqrt{3} - 1) sin θ + (\sqrt{3} + 1) cos θ = 2

is
(where

n \in Z

)

Join BYJU'S Learning Program

Solving sinθ=√32 then, θ=nπ+(−1)nπm,n∈I. Find m

sinθ=√32⇒sinθ=sinπ3∴θ=nπ+(−1)nπ3,n∈I

Solving $sin θ = \frac{\sqrt{3}}{2}$ then, $θ = n π + {(- 1)}^{n} \frac{π}{m}, n \in I$ . Find $m$

$sin θ = \frac{\sqrt{3}}{2}$
$\Rightarrow sin θ = sin \frac{π}{3}$
$∴ θ = n π + {(- 1)}^{n} \frac{π}{3}, n \in I$