Question

Solving the following quadratic equation by factorization, the roots are :$-\frac{3}{2},\frac{-1}{3}$
$6x^2$ + 11x + 3 = 0

• A. True
• B. False

Answer 1

The correct option is A True

$6x^2+11x+3=0$

$\Rightarrow$ $6x^2+9x+2x+3=0$

$\Rightarrow$ $3x(2x+3)+1(2x+3)=0$

$\Rightarrow$ $(2x+3)(3x+1)=0$

$\Rightarrow$ $2x+3=0$ and $3x+1=0$

$\Rightarrow$ $x=-\frac{3}{2}$ and $x=-\frac{1}{3}$

$\therefore$ We can see that, roots given in question are correct.