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Question

Solving the following quadratic equations by factorization method:
(i) x2+10ix-21=0
(ii) x2+1-2i x-2i=0
(iii) x2-23+3i x+63i=0
(iv) 6x2-17ix-12=0

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Solution

i x2+10ix-21=0x2+7ix+3ix-21=0xx+7i+3ix+7i=0x+7ix+3i=0x+7i=0 or x+3i=0x=-7i, -3iSo, the roots of the given quadratic equation are -3i and -7i.

ii x2+1-2i x-2i=0 x2+x-2ix-2i=0xx+1-2ix+1=0x+1x-2i=0x+1=0 or x-2i=0x=-1, 2iSo, the roots of the given quadratic equation are -1 and 2i.

iii x2-23+3i x+63i=0 x2-23x-3i x+63i=0xx-23-3ix-23=0x-23x-3i=0x-23=0 or x-3i=0x=23, 3iSo, the roots of the given quadratic equation are 23 and 3i.

iv 6x2-17ix-12=06x2-9ix-8ix-12=03x2x-3i-4i2x-3i=02x-3i3x-4i=02x-3i=0 or 3x-4i=0x=32i, 43iSo, the roots of the given quadratic equation are 32i and 43i.

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