Question

Solving the linear equation 3(4m - 5)= $\frac{4}{5}$(2m + $\frac{3}{4}$) for m, we get .

• A. $\frac{5}{2}$
• B. 1$\frac{4}{5}$
• C. 1$\frac{1}{2}$

Answer 1

The correct option is C 1$\frac{1}{2}$

Given expression is
3(4$m$ - 5) = $\frac{4}{5}$(2$m$ + $\frac{3}{4}$)

$\Rightarrow$ 12$m$ - 15 = $\frac{8m}{5}$ + $\frac{3}{5}$

Adding 15 on both sides, we get,

$\Rightarrow$ 12$m$ - 15 + 15 = $\frac{8m}{5}$ + $\frac{3}{5}$ + 15

$\Rightarrow$ 12$m$ = $\frac{8m}{5}$ + $\frac{3}{5}$ + 15

$\Rightarrow$ 12$m$ - $\frac{8m}{5}$ = $\frac{3}{5}$ + 15

Taking LCM on both sides,

$\Rightarrow$ $\frac{60m-8m}{5}$ = $\frac{3+75}{5}$

$\Rightarrow$ $\frac{52m}{5}$ = $\frac{78}{5}$

$\Rightarrow$ 52$m$ = 78

$\Rightarrow$ $m$ = $\frac{78}{52}$

$\Rightarrow$ $m$ = $\frac{39}{26}$

$\Rightarrow$ $m$ = $\frac{3}{2}$

$\Rightarrow$ $m$ = 1$\frac{1}{2}$