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Specific Heat Capacity

Some hot wate...

Question

Some hot water was added to three times its mass of cold water at 10 $^{0} C$ and the resulting temperature was found to be 20 $^{0} C$ . What was the temperature of the hot water?

200⁰C

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59⁰C

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50⁰C

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273⁰C

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Solution

The correct option is C
50⁰C

Let the mass of hot water be m and temperature of hot water be $θ$

Mass of cold water = 3 m

According to principle of mixtures

Heat lost by hot water = Heat gained by cold water

m c $(θ - 20) = 3 m \times c (20 - 10)$

$θ - 20 = 30; θ = 50^{0} C$

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Similar questions

Q. Certain amount of hot water was added to three times its mass of cold water at

10^{\circ} C

. The resulting temperature was found to be

20^{\circ} C

. The initial temperature of the hot water is:

The temperature of 600 g of cold water rises by $15^{\circ} C$ when 300 g of hot water at $50^{\circ} C$ is added to it. What was the initial temperature of the cold water?

Q. The temperature of

600

g of cold water rises by

15^{o} C

when

300

g of hot water at

50^{\circ} C

is added to it. What was the initial temperature of the cold water?

Q. The temperature of

600

g of cold water rises by

15

^{\circ}

C, when

300

g of hot water

50

^{\circ}

C is added to it. What was the initial temperature of the cold water?

20 g

of ice and

20 g

of hot water are mixed, when the ice is melted the temperature of the mixture was found to be

0^{o} C

. The temperature of hot water taken should be

(

L_{i c e} =

80 cal/g)

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Some hot water was added to three times its mass of cold water at 100C and the resulting temperature was found to be 200C. What was the temperature of the hot water?

The correct option is C 500C Let the mass of hot water be m and temperature of hot water be θ Mass of cold water = 3 m According to principle of mixtures Heat lost by hot water = Heat gained by cold water m c(θ−20)=3m×c(20–10) θ−20=30;θ=500C

Some hot water was added to three times its mass of cold water at 10 $^{0} C$ and the resulting temperature was found to be 20 $^{0} C$ . What was the temperature of the hot water?

The correct option is C
50⁰C

Let the mass of hot water be m and temperature of hot water be $θ$

Mass of cold water = 3 m

According to principle of mixtures

Heat lost by hot water = Heat gained by cold water

m c $(θ - 20) = 3 m \times c (20 - 10)$

$θ - 20 = 30; θ = 50^{0} C$