Question

Some non-metals when treated with $NaOH$ disproportionate. They may be:
(i) $P_4$
(ii) $S_8$
(iii) $C{l}_2$

• A. Both (i) and (ii)
• B. (i), (ii) and (iii)
• C. Only (ii)
• D. (ii) and (iii)

Answer 1

The correct option is B

(i), (ii) and (iii)

$12NaOH+S_8\to 4N{a}_{2}S+2N{a}_2{S}_2{O}_3+6H_{2}O$
$3NaOH+P_4+3H_{2}O\to 3Na{H}_{2}P{O}_2+P{H}_3$
$2NaOH(cold,dil.)+C{l}_2\to NaCl+NaClO+H_{2}O$
$6NaOH(hot,conc.)+3C{l}_2\to 5NaCl+NaCl{O}_3+3H_{2}O$