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Question

Sonu is 5 years elder to his brother. 4 years ago Sonu was twice age of his brother. Find their present ages.

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Solution

Let the present age of Sonu's brother is x years .Then Sonu's age will be x+5 years .4 Years agoAge of Sonu's brother =x-4 years .Age of sonu = x+5-4=x+1 Years .A.T.Qx+1=2x-4x+1=2x-8x-2x=-8-1-x=-9x=9 years .So, Age of Sonu's brother is 9 years .AndAge of Sonu = x+5=9+5=14 years .

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