Question

Sonu is 5 years elder to his brother. 4 years ago Sonu was twice age of his brother. Find their present ages.

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{present}\mathrm{age}\mathrm{of}\mathrm{Sonu}\text{'}\mathrm{s}\mathrm{brother}\mathrm{is}\mathrm{x}\mathrm{years}. \\ \mathrm{Then}\mathrm{Sonu}\text{'}\mathrm{s}\mathrm{age}\mathrm{will}\mathrm{be}\left(\mathrm{x}+5\right)\mathrm{years}. \\ 4\mathrm{Years}\mathrm{ago} \\ \mathrm{Age}\mathrm{of}\mathrm{Sonu}\text{'}\mathrm{s}\mathrm{brother}=\left(\mathrm{x}-4\right)\mathrm{years}. \\ \mathrm{Age}\mathrm{of}\mathrm{sonu}=\left(\mathrm{x}+5-4\right)=\left(\mathrm{x}+1\right)\mathrm{Years}. \\ \mathrm{A}.\mathrm{T}.\mathrm{Q} \\ \left(\mathrm{x}+1\right)=2\left(\mathrm{x}-4\right) \\ \mathrm{x}+1=2\mathrm{x}-8 \\ \mathrm{x}-2\mathrm{x}=-8-1 \\ -\mathrm{x}=-9 \\ \mathrm{x}=9\mathrm{years}. \\ \mathrm{So},\mathrm{Age}\mathrm{of}\mathrm{Sonu}\text{'}\mathrm{s}\mathrm{brother}\mathrm{is}9\mathrm{years}. \\ \mathrm{And} \\ \mathrm{Age}\mathrm{of}\mathrm{Sonu}=\mathrm{x}+5=9+5=14\mathrm{years}. \end{gathered}$$