Sony car sales to jewellery boxes for 1400 each on one she earns a profit of 10% and on the other suffers a loss of 10% find overall profit or loss percent

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Solution

$SP of first jewellery box = Rs 1400 Profit % = 10 % Let the CP of first jewellery box = Rs x Profit % = 10 % \Rightarrow [\frac{profit}{CP} \times 100] % = 10 % \Rightarrow \frac{profit}{x} \times 100 = 10 \Rightarrow 10 profit = x \Rightarrow 10 (SP - CP) = x \Rightarrow 10 [1400 - x] = x \Rightarrow 14000 - 10 x = x \Rightarrow 11 x = 14000 \Rightarrow x = Rs (\frac{14000}{11}) So, CP of first box = Rs (\frac{14000}{11}) SP of second jewellery box = Rs 1400 loss % = 10 % Let the CP of secondjewellery box = Rs y loss % = 10 % \Rightarrow [\frac{loss}{CP} \times 100] % = 10 % \Rightarrow \frac{loss}{y} \times 100 = 10 \Rightarrow 10 loss = y \Rightarrow 10 (CP - SP) = y \Rightarrow 10 [y - 1400] = y \Rightarrow 10 y - 14000 = y \Rightarrow 9 y = 14000 \Rightarrow y = \frac{14000}{9} CP of second jewellery box = Rs (\frac{14000}{9}) Total SP of both boxes = 1400 + 1400 = Rs 2800 Total CP of both boxes = \frac{14000}{11} + \frac{14000}{9} = \frac{126000 + 154000}{99} = Rs (\frac{280000}{99}) = Rs 2828.28 Net loss = Total CP - Total SP = 2828.28 - 2800 = Rs 28.28 Loss % = [\frac{loss}{CP} \times 100] % = [\frac{28.28}{2828.28} \times 100] % = 0.99 %$

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