Sort out following halogens in decreasing order of their leaving capacity in $S_{N} 2$ reaction

F

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B r

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I

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C l

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Solution

A good leaving group is conjugate base of strong acid. The acidic strength of the given acids can be given as:
$H I > H B r > H C l > H F$
So, the the order for leaving group will be:
$I^{-} > B r^{-} > C l^{-} > F^{-}$

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Sort out following halogens in decreasing order of their leaving capacity in SN2 reaction

A good leaving group is conjugate base of strong acid. The acidic strength of the given acids can be given as: HI>HBr>HCl>HF So, the the order for leaving group will be: I−>Br−>Cl−>F−

Sort out following halogens in decreasing order of their leaving capacity in $S_{N} 2$ reaction

A good leaving group is conjugate base of strong acid. The acidic strength of the given acids can be given as:
$H I > H B r > H C l > H F$
So, the the order for leaving group will be:
$I^{-} > B r^{-} > C l^{-} > F^{-}$