Question

Sort the following algebraic equations according to the decreasing order of the values of their unknowns.

• A. $x÷6=3$
• B. $y+7=17$
• C. $u-4=21$
• D. $v\times 10=80$

Answer 1

A. $u-4=21$

Adding $4$ on both sides

$u-4+4=21+4\Rightarrow u=25$

This would give the value of '$u$' as 25.

B. $x÷6=3$

Multiplying with $6$:

$\frac{6\times x}{6}=3\times 6\Rightarrow x=18$

This would give the value of '$x$' as 18.

C. $y+7=17$

Subtracting by $7$ on both sides:

$y+7-7=17-7\Rightarrow y=10$

This would give the value of '$y$' as 10.

D. $v\times 10=80$

Dividing with $10$:

$\frac{10\times v}{10}=\frac{80}{10}\Rightarrow v=8$

The value of '$v$' is 8.

The decreasing order of the values of unknowns would be:
$u>x>y>v$.