Question

Sort the following in the ascending order of their values from top to bottom.

• A. $2^2$
• B. $2^3$
• C. $(-3{)}^3$
• D. $3^2$

Answer 1

$3^2=3\times 3=9$
$(-3{)}^3=(-3)\times (-3)\times (-3)=-27$
$2^3=2\times 2\times 2=8$
$2^2=2\times 2=4$

Now its clear that -27 < 4 < 8 < 9.
$\therefore (-3{)}^3<2^2<2^3<3^2$